Various combinatorial problems have been reduced to the Chinese Postman Problem, including finding a maximum cut in a planar graph and a minimum-mean length circuit in an undirected graph. See more In graph theory, a branch of mathematics and computer science, Guan's route problem, the Chinese postman problem, postman tour or route inspection problem is to find a shortest closed path or circuit that visits every … See more On a directed graph, the same general ideas apply, but different techniques must be used. If the directed graph is Eulerian, one need only find an Euler cycle. If it is not, one must find T-joins, which in this case entails finding paths from vertices with an in- See more • Weisstein, Eric W., "Chinese Postman Problem", MathWorld • Media related to Route inspection problem at Wikimedia Commons See more The undirected route inspection problem can be solved in polynomial time by an algorithm based on the concept of a T-join. Let T be a set of vertices in a graph. An edge set J is called a T-join if the collection of vertices that have an odd number of incident … See more A few variants of the Chinese Postman Problem have been studied and shown to be NP-complete. • The windy postman problem is a variant of the route … See more • Travelling salesman problem • Arc routing • Mixed Chinese postman problem See more WebNov 28, 2014 · The Chinese Postman Problem was first posed by a Chinese mathematician in 1962. It involved trying to calculate how a postman …
6.4.4 Solving the Chinese Postman
WebJan 1, 2005 · A generalization of the Chinese Postman Problem is considered, in which a linear order on a set of important nodes is given and the task is to traverse all edges at least once in such a way... WebThe Chinese Postman Problem (Introduction to Graph Theory) - YouTube This video covers Eulerian, Semi-Eulerian, and regular graphs in the Chinese Postman Problem as well as applications... fisher png
4.6 The Chinese Postman Problem - USTC
WebThen R correspondsto a postman walk W for N with length(W) = length(R) = w(N ). Hence N has a postman walk of length k. 8.7 Corollary The minimum length of a postman walk of N is equal to the minimum weight of an Eulerian extension of N. Proof Take k as small as possible in Lemma 8.6 We will solve the Chinese Postman problem for a network N by ... WebThe starting graph is undirected.That is, your edges have no orientation: they are bi-directional.For example: A<--->B == B<--->A.By contrast, the graph you might create to … WebConsider again our initial Chinese Postman problem shown in Figure 6.12. The odd-degree nodes on Figure 6.12 are C, D, F, G, I, J, K, and L. They are shown on Figure 6.17, with that part of the network model of the … fisher podiatry